Let theta be angle between tangent at t and the chord from t to t+s on a [arc length parameterized] convex curve. Let r be the distance between points at t and t+s. Let psi be the angle between the chord and the tangent at t+s.
To find nth derivative in r of cos(theta) as r->0.
Let D = d()/dr, Dn the n-th such derivative and let L = lim as r->0. The problem is to find L*Dn( cos(theta) )
Lemma 1:
D(theta) = -tan(psi)/r
D(psi) = D(theta) - kappa*sec(psi)
where kappa is the curvature at t+s
Dn+1(kappa) = -Dn(kappa)*sec(psi)
Lemma 2:
L(theta) = 0L(psi) = PI
L(Dn(kappa)) = ki (a definition)
L(D1(theta)) = -k0/2
L(D2(theta)) = k1/3 [or is it -(k0/2)^2??]
Speculation: the successive answers, given in terms of polynomials in the ki's, form a Tauberian collection of polynomials, sufficient to reconstruct the complete original kappa - and hence the curve [usually!] If I had been a smart mathematician, I would have proved "Tauberian" without the explicit calculations.
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